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Air Mass - Extinction

An effect which must be corrected when calibrating instrumental magnitudes, is the atmospheric extinction or the dimming of starlight. The longer the path length the starlight traverses through the atmosphere the more it is dimmed. Thus, a star close to the horizon will be dimmed more than one close to the zenith, and the observed brightness of a given star will change throughout a night, as its zenith distance varies. The path length through the atmosphere is known as the air mass. Consider an observation through the blanket of the atmosphere around the curved surface of the Earth. At any particular wavelength, $ \lambda$,we can relate $ m_0(\lambda)$, the magnitude of the observed object outside the atmosphere, to $ m(\lambda)$, the magnitude of the observed object at the surface of the earth, by:

$\displaystyle m(\lambda) = m_0(\lambda) + \kappa(\lambda)X(z)$ (1.1)

where $ X(z)$ is the air mass, $ \kappa(\lambda)$ is the extinction coefficient at wavelength $ \lambda$ and $ z$ is the zenith distance (the angular distance of the object from the zenith at the time of observation). $ X$ is defined as the number of times the quantity of air seen along the line of sight is greater than the quantity of air in the direction of the zenith and will vary as the observed line of sight moves away from the zenith, that is, as $ z$ increases. Note that the air mass is a normalised quantity and the air mass at the zenith is one. For small zenith angles $ X=\sec z$ is a reasonable approximation, but as $ z$ increases, refraction effects, curvature of the atmosphere and variations of air density with height can become important. Hardie gives a more refined relationship:

$\displaystyle X= \sec z - 0.0018167(\sec z -1) - 0.002875(\sec z -1)^2 - 0.0008083(\sec z -1)^3$ (1.2)

and Young and Irvine propose :

$\displaystyle X= \sec z \left( 1 - 0.0012 (\sec^2 z-1) \right)$ (1.3)

Both these equations imply the use of $ z_t$, the true zenith angle, that is, the zenith angle to the observed object in the absence of the atmosphere as opposed to the apparent zenith angle $ z_a$ affected by refraction effects. The atmospheric extinction coefficient, $ \kappa(\lambda)$, can be determined by observing the same object (through an appropriate filter) at several times during the night at varying zenith angles. When the observed magnitudes of the object are plotted against computed air mass (see Figure 1.1), they should lie on a straight line with a slope equal to $ \kappa(\lambda)$. It is important to note that the extinction is dependent upon wavelength, being greater for blue light than red.
Figure 1.1: Calculation of extinction coefficient.
Image img48


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